What is the derivative of f(2)=-x^2+6x-3 ?

The derivative of f(2)=-x^2+6x-3 is -2x+6

What is the first derivative of f(2)=-x^2+6x-3 ?

The first derivative of f(2)=-x^2+6x-3 is -2x+6

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derivative of

f (2) = - x^{2} + 6 x - 3

- 2 x + 6

Solution steps

\frac{d}{d x} (- x^{2} + 6 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (3) = 0

= - 2 x + 6 - 0

Simplify

= - 2 x + 6

\frac{x}{1 + x ^{2}}, \frac{x ^{2}}{1 + x ^{3}}

\frac{d}{d x} (\frac{1}{4} sin (4 x))

n = 1 \sum \infty (\frac{2}{3})^{n - 1}

x \to o lim (f (x))

f (x) = x^{3} - 2 x^{2} - 2 x + 1

What is the derivative of f(2)=-x^2+6x-3 ?
The derivative of f(2)=-x^2+6x-3 is -2x+6
What is the first derivative of f(2)=-x^2+6x-3 ?
The first derivative of f(2)=-x^2+6x-3 is -2x+6