What is the integral from 0 to infinity of e^{-t} ?

The integral from 0 to infinity of e^{-t} is 1

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integral from 0 to infinity of e^{-t}

\int_{0}^{\infty} e^{- t} d t

1

Solution steps

\int_{0}^{\infty} e^{- t} d t

Compute the indefinite integral:

\int e^{- t} d t = - e^{- t} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- t} d t = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

\frac{d}{d x} (5 x^{2} + 3 x - 1)

\frac{1}{2 y}

\frac{16}{( 5 - x ) ^{2}} - 1

\frac{\partial}{\partial x} (arcsin (3 x - 2))

f (x) = \frac{x}{x ^{2} - 16}

What is the integral from 0 to infinity of e^{-t} ?
The integral from 0 to infinity of e^{-t} is 1