What is the solution for (dy)/(dx)=sqrt(x^9+1) ?

The solution for (dy)/(dx)=sqrt(x^9+1) is y=integral of sqrt(x^9+1)

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(dy)/(dx)=sqrt(x^9+1)

\frac{d y}{d x} = x^{9} + 1

y = \int x^{9} + 1 d x

Solution steps

\frac{d y}{d x} = x^{9} + 1

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = x^{9} + 1

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{9} + 1 d x

y = \int x^{9} + 1 d x

t^{2} \frac{d y}{d t} + 4 t y - y^{3} = 0, y (1) = \frac{3}{2}

y = \frac{3}{sin ( x ) + cos ( x )}

\int \frac{48}{36 - x ^{2}} d x

\frac{d}{d x} (\frac{( x + b ) ( x - a )}{( x - b )})

f (x) = 4 x + 84, (4, 10)

What is the solution for (dy)/(dx)=sqrt(x^9+1) ?
The solution for (dy)/(dx)=sqrt(x^9+1) is y=integral of sqrt(x^9+1)