What is the integral of 8xsqrt(1-x^2) ?

The integral of 8xsqrt(1-x^2) is -8/3 (1-x^2)^{3/2}+C

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integral of 8xsqrt(1-x^2)

\int 8 x 1 - x^{2} d x

- \frac{8}{3} (1 - x^{2})^{\frac{3}{2}} + C

Solution steps

\int 8 x 1 - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int x 1 - x^{2} d x

Apply u-substitution

: \int - u^{2} d u

= 8 \cdot \int - u^{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 (- \int u^{2} d u)

Apply the Power Rule

: \frac{u ^{3}}{3}

= 8 (- \frac{u ^{3}}{3})

Substitute back

u = 1 - x^{2}

= 8 (- \frac{( 1 - x ^{2} ) ^{3}}{3})

Simplify

8 (- \frac{( 1 - x ^{2} ) ^{3}}{3}) : - \frac{8}{3} (1 - x^{2})^{\frac{3}{2}}

= - \frac{8}{3} (1 - x^{2})^{\frac{3}{2}}

Add a constant to the solution

= - \frac{8}{3} (1 - x^{2})^{\frac{3}{2}} + C

\frac{d}{d x} (\frac{20 x ^{2}}{( x - 1 ) ^{3}})

f (x) = \frac{1}{( 2 x - 1 ) ^{6}}, at x = 1

x \to - 2 lim (8 + x^{3})

\frac{d}{d a} (\frac{cos ^{2} ( a )}{1 - sin ( a )})

\int 10 + 6 x + 36 x^{2} d x

What is the integral of 8xsqrt(1-x^2) ?
The integral of 8xsqrt(1-x^2) is -8/3 (1-x^2)^{3/2}+C