What is the limit as x approaches-1 of x/(x+1) ?

The limit as x approaches-1 of x/(x+1) is diverges

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limit as x approaches-1 of x/(x+1)

x \to - 1 lim (\frac{x}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x}{x + 1}) = - \infty

x \to - 1 - lim (\frac{x}{x + 1}) = \infty

= diverges

\frac{d}{d x} ((ln (3))^{x})

x^{4} - 5 x^{2} + 4, at x = 1

\frac{d y}{d t} = 2 y - y^{2}

\int 1 - sin (2 x) d x

x, \frac{1}{18 x ^{2}}, \frac{x}{16}

What is the limit as x approaches-1 of x/(x+1) ?
The limit as x approaches-1 of x/(x+1) is diverges