What is the integral of (\sqrt[14]{x}+\sqrt[15]{x}) ?

The integral of (\sqrt[14]{x}+\sqrt[15]{x}) is 14/15 x^{15/14}+15/16 x^{16/15}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (\sqrt[14]{x}+\sqrt[15]{x})

\frac{14}{15} x^{\frac{15}{14}} + \frac{15}{16} x^{\frac{16}{15}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{14}{15} x^{\frac{15}{14}} + \frac{15}{16} x^{\frac{16}{15}}

Add a constant to the solution

= \frac{14}{15} x^{\frac{15}{14}} + \frac{15}{16} x^{\frac{16}{15}} + C

f (x) = 7 x - 4 x^{2}, (- 1, - 11)

f (x) = \frac{5}{x - 7}, (8, 5)

y = x^{16}

\frac{d y}{d x} = x - 2 y

\frac{x}{x}

What is the integral of (\sqrt[14]{x}+\sqrt[15]{x}) ?
The integral of (\sqrt[14]{x}+\sqrt[15]{x}) is 14/15 x^{15/14}+15/16 x^{16/15}+C