What is the derivative of (4x+1)^2 ?

The derivative of (4x+1)^2 is 8(4x+1)

What is the first derivative of (4x+1)^2 ?

The first derivative of (4x+1)^2 is 8(4x+1)

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derivative of

(4 x + 1)^{2}

8 (4 x + 1)

Solution steps

\frac{d}{d x} ((4 x + 1)^{2})

Apply the chain rule:

2 (4 x + 1) \frac{d}{d x} (4 x + 1)

= 2 (4 x + 1) \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 2 (4 x + 1) \cdot 4

Simplify

= 8 (4 x + 1)

f (x) = (x^{3} - 25 x)^{14}, (5, 0)

t \to 0 lim (ln (sin (4 t)))

\frac{\partial}{\partial x} (e^{\frac{2 x + 3 y}{3 y}})

\frac{d}{d x} (5 (e^{x})^{- 4})

x \to 2 lim (12 x^{2})

What is the derivative of (4x+1)^2 ?
The derivative of (4x+1)^2 is 8(4x+1)
What is the first derivative of (4x+1)^2 ?
The first derivative of (4x+1)^2 is 8(4x+1)