What is the derivative of 7x^2(x-4)^3 ?

The derivative of 7x^2(x-4)^3 is 7(2x(x-4)^3+3(x-4)^2x^2)

What is the first derivative of 7x^2(x-4)^3 ?

The first derivative of 7x^2(x-4)^3 is 7(2x(x-4)^3+3(x-4)^2x^2)

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derivative of

7 x^{2} (x - 4)^{3}

7 (2 x (x - 4)^{3} + 3 (x - 4)^{2} x^{2})

Solution steps

\frac{d}{d x} (7 x^{2} (x - 4)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (x^{2} (x - 4)^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = (x - 4)^{3}

= 7 (\frac{d}{d x} (x^{2}) (x - 4)^{3} + \frac{d}{d x} ((x - 4)^{3}) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} ((x - 4)^{3}) = 3 (x - 4)^{2}

= 7 (2 x (x - 4)^{3} + 3 (x - 4)^{2} x^{2})

\int \frac{5 x ^{2}}{4 x - x ^{2}} d x

\int \frac{4}{u} d u

n = 2 \sum \infty e^{5 - 2 n}

x^{2} y^{^{'}} + y^{2} - x y = 0

\int \frac{x - 3}{x + 4} d x

What is the derivative of 7x^2(x-4)^3 ?
The derivative of 7x^2(x-4)^3 is 7(2x(x-4)^3+3(x-4)^2x^2)
What is the first derivative of 7x^2(x-4)^3 ?
The first derivative of 7x^2(x-4)^3 is 7(2x(x-4)^3+3(x-4)^2x^2)