What is the solution for x^{''}-20x^'+91x=0 ?

The solution for x^{''}-20x^'+91x=0 is x=c_{1}e^{13t}+c_{2}e^{7t}

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x^{''}-20x^'+91x=0

x^{^{''}} - 20 x^{^{'}} + 91 x = 0

x = c_{1} e^{13 t} + c_{2} e^{7 t}

Solution steps

x^{''} (t) - 20 x^{'} (t) + 91 x = 0

Solve linear ODE:

x = c_{1} e^{13 t} + c_{2} e^{7 t}

x = c_{1} e^{13 t} + c_{2} e^{7 t}

f (t) = t^{\frac{1}{2}} (13 t + 2)

\frac{9}{( 9 - x ^{8} ) ^{\frac{3}{2}}}

\int_{3}^{5} \frac{x ^{2}}{8} d x

n = 1 \sum \infty \frac{n}{1000 n + 1}

\frac{d}{d x} (3^{x} x^{3})

What is the solution for x^{''}-20x^'+91x=0 ?
The solution for x^{''}-20x^'+91x=0 is x=c_{1}e^{13t}+c_{2}e^{7t}