What is (\partial)/(\partial y)(xye^{-5y}) ?

The answer to (\partial)/(\partial y)(xye^{-5y}) is x(e^{-5y}-5e^{-5y}y)

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(\partial)/(\partial y)(xye^{-5y})

\frac{\partial}{\partial y} (x y e^{- 5 y})

x (e^{- 5 y} - 5 e^{- 5 y} y)

Solution steps

\frac{\partial}{\partial y} (x y e^{- 5 y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial y} (y e^{- 5 y})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = e^{- 5 y}

= x (\frac{\partial}{\partial y} (y) e^{- 5 y} + \frac{\partial}{\partial y} (e^{- 5 y}) y)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (e^{- 5 y}) = - 5 e^{- 5 y}

= x (1 \cdot e^{- 5 y} + (- 5 e^{- 5 y}) y)

Simplify

= x (e^{- 5 y} - 5 e^{- 5 y} y)

\frac{d}{d x} (\frac{16}{x ^{3}})

5 y^{^{'}} + y = - 3

f (x) = 3 x^{4} - 8 x^{3} + 2

\frac{d}{d x} (5 e^{- 2 x} sin (3 x))

(1 + x)^{- \frac{5}{3}}

What is (\partial)/(\partial y)(xye^{-5y}) ?
The answer to (\partial)/(\partial y)(xye^{-5y}) is x(e^{-5y}-5e^{-5y}y)