What is the derivative of 1/((x+8^2)) ?

The derivative of 1/((x+8^2)) is -2/((x+8)^3)

What is the first derivative of 1/((x+8^2)) ?

The first derivative of 1/((x+8^2)) is -2/((x+8)^3)

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\frac{d}{d x} (\frac{1}{( x + 8 ) ^{2}})

- \frac{2}{( x + 8 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x + 8 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 8)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 8 ) ^{3}} \frac{d}{d x} (x + 8)

= - \frac{2}{( x + 8 ) ^{3}} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= - \frac{2}{( x + 8 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( x + 8 ) ^{3}}

\int \frac{1}{x ^{2} ( x - 2 )} d x

\int_{0}^{3} 3 x^{3} d x

\frac{1}{2 + t}

\int 8 csc (x) d x

f (x) = 5 x + 39, at x = 5

What is the derivative of 1/((x+8^2)) ?
The derivative of 1/((x+8^2)) is -2/((x+8)^3)
What is the first derivative of 1/((x+8^2)) ?
The first derivative of 1/((x+8^2)) is -2/((x+8)^3)