What is (\partial)/(\partial y)(x+sqrt(x^2+y^2)) ?

The answer to (\partial)/(\partial y)(x+sqrt(x^2+y^2)) is y/(sqrt(x^2+y^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x+sqrt(x^2+y^2))

\frac{\partial}{\partial y} (x + x^{2} + y^{2})

\frac{y}{x ^{2} + y ^{2}}

Solution steps

\frac{\partial}{\partial y} (x + x^{2} + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (x^{2} + y^{2})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (x^{2} + y^{2}) = \frac{y}{x ^{2} + y ^{2}}

= 0 + \frac{y}{x ^{2} + y ^{2}}

Simplify

= \frac{y}{x ^{2} + y ^{2}}

\frac{d}{d x} (\frac{6 x - 1}{4 x + 3})

\frac{\partial}{\partial v} (u v^{2})

\frac{d}{d x} (\frac{1}{( x + 8 ) ^{2}})

\int \frac{1}{x ^{2} ( x - 2 )} d x

\int_{0}^{3} 3 x^{3} d x

What is (\partial)/(\partial y)(x+sqrt(x^2+y^2)) ?
The answer to (\partial)/(\partial y)(x+sqrt(x^2+y^2)) is y/(sqrt(x^2+y^2))