What is (\partial)/(\partial v)(uv^2) ?

The answer to (\partial)/(\partial v)(uv^2) is 2uv

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(\partial)/(\partial v)(uv^2)

\frac{\partial}{\partial v} (u v^{2})

2 uv

Solution steps

\frac{\partial}{\partial v} (u v^{2})

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= u \frac{\partial}{\partial v} (v^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= u \cdot 2 v^{2 - 1}

Simplify

= 2 uv

\frac{d}{d x} (\frac{1}{( x + 8 ) ^{2}})

\int \frac{1}{x ^{2} ( x - 2 )} d x

\int_{0}^{3} 3 x^{3} d x

\frac{1}{2 + t}

\int 8 csc (x) d x

What is (\partial)/(\partial v)(uv^2) ?
The answer to (\partial)/(\partial v)(uv^2) is 2uv