What is the derivative of f(x)=sqrt(3-4x) ?

The derivative of f(x)=sqrt(3-4x) is -2/(sqrt(3-4x))

What is the first derivative of f(x)=sqrt(3-4x) ?

The first derivative of f(x)=sqrt(3-4x) is -2/(sqrt(3-4x))

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derivative of

f (x) = 3 - 4 x

- \frac{2}{3 - 4 x}

Solution steps

\frac{d}{d x} (3 - 4 x)

Apply the chain rule:

\frac{1}{2 3 - 4 x} \frac{d}{d x} (3 - 4 x)

= \frac{1}{2 3 - 4 x} \frac{d}{d x} (3 - 4 x)

\frac{d}{d x} (3 - 4 x) = - 4

= \frac{1}{2 3 - 4 x} (- 4)

Simplify

\frac{1}{2 3 - 4 x} (- 4) : - \frac{2}{3 - 4 x}

= - \frac{2}{3 - 4 x}

n = 0 \sum \infty \frac{1}{3} \cdot (\frac{1}{3})^{n}

\int x^{2} sin (z x) d x

y^{^{'}} + \frac{4}{x} y = x^{9}

x \to \infty lim (arctan (\frac{( 1 - x ^{2} )}{( 1 + x )}))

\frac{d y}{d x} = 0.067 y (1 - \frac{y}{2800})

What is the derivative of f(x)=sqrt(3-4x) ?
The derivative of f(x)=sqrt(3-4x) is -2/(sqrt(3-4x))
What is the first derivative of f(x)=sqrt(3-4x) ?
The first derivative of f(x)=sqrt(3-4x) is -2/(sqrt(3-4x))