What is the solution for (dy)/(dx)=(y-1)^2+0.01 ?

The solution for (dy)/(dx)=(y-1)^2+0.01 is y=(tan(\frac{x+c_{1})/(10))}{10}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y-1)^2+0.01

\frac{d y}{d x} = (y - 1)^{2} + 0.01

y = \frac{tan ( \frac{x + c _{1}}{10} )}{10} + 1

Solution steps

\frac{d y}{d x} = (y - 1)^{2} + 0.01

Solve separable ODE:

y = \frac{tan ( \frac{x + c _{1}}{10} )}{10} + 1

y = \frac{tan ( \frac{x + c _{1}}{10} )}{10} + 1

h (x) = (- 3 x + 2)^{4} (- 2 x + 3)^{3}

\int t^{2} sin (β) t d t

\int csc (x) cot (x) d x

f (x) = - 8 x sin (4 x^{2} + 1)

What is the solution for (dy)/(dx)=(y-1)^2+0.01 ?
The solution for (dy)/(dx)=(y-1)^2+0.01 is y=(tan(\frac{x+c_{1})/(10))}{10}+1