What is the derivative of-e^{-2x} ?

The derivative of-e^{-2x} is 2e^{-2x}

What is the first derivative of-e^{-2x} ?

The first derivative of-e^{-2x} is 2e^{-2x}

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\frac{d}{d x} (- e^{- 2 x})

2 e^{- 2 x}

Solution steps

\frac{d}{d x} (- e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= - e^{- 2 x} (- 2)

Simplify

= 2 e^{- 2 x}

f (x) = 5 x + 4, at x = 9

y^{^{''}} + 10 y^{^{'}} + 25 y = 2 r^{- 5 x}

\int ln (x^{\frac{1}{3}}) d x

\int (3 - cos^{3} (x)) sin (x) d x

3 sin (4 t)

What is the derivative of-e^{-2x} ?
The derivative of-e^{-2x} is 2e^{-2x}
What is the first derivative of-e^{-2x} ?
The first derivative of-e^{-2x} is 2e^{-2x}