What is the solution for (dx)/(dt)=2tcos^2(x) ?

The solution for (dx)/(dt)=2tcos^2(x) is x=arctan(t^2+c_{1})+pin

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(dx)/(dt)=2tcos^2(x)

\frac{d x}{d t} = 2 t cos^{2} (x)

x = arctan (t^{2} + c_{1}) + πn

Solution steps

\frac{d x}{d t} = 2 t cos^{2} (x)

Solve separable ODE:

x = arctan (t^{2} + c_{1}) + πn

x = arctan (t^{2} + c_{1}) + πn

\frac{d}{d x} (3 x^{2} + ln (5 x) - sin (x))

\frac{d}{d j} (2 i - 3 j)

y^{^{'}} + \frac{5}{t} y = 1

\int arccot (5 y) d y

f (x) = x^{2} - 6, (4, 10)

What is the solution for (dx)/(dt)=2tcos^2(x) ?
The solution for (dx)/(dt)=2tcos^2(x) is x=arctan(t^2+c_{1})+pin