What is laplacetransform e^{3a-bt} ?

The answer to laplacetransform e^{3a-bt} is (e^{3a})/(s+b)

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laplacetransform e^{3a-bt}

laplace transform

e^{3 a - b t}

\frac{e ^{3 a}}{s + b}

Solution steps

L {e^{3 a - b t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{3 a} L {e^{- b t}}

L {e^{- b t}} : \frac{1}{s + b}

= e^{3 a} \frac{1}{s + b}

Refine

e^{3 a} \frac{1}{s + b} : \frac{e ^{3 a}}{s + b}

= \frac{e ^{3 a}}{s + b}

\int \frac{11 x ^{3}}{4 + x ^{2}} d x

x \to - 1 lim (x^{5} + 4 x^{2} + x)

\frac{d}{d x} (x^{2} - 2 x y)

\frac{d}{d x} (\frac{k}{x})

x \to 3 lim (\frac{∣ x - 3 ∣}{x - 3})

What is laplacetransform e^{3a-bt} ?
The answer to laplacetransform e^{3a-bt} is (e^{3a})/(s+b)