What is the solution for y^'-6/x y=(y^4)/(x^{15)} ?

The solution for y^'-6/x y=(y^4)/(x^{15)} is y=(\sqrt[3]{4}x^6)/(\sqrt[3]{-3x^4+c_{1)}}

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y^'-6/x y=(y^4)/(x^{15)}

y^{^{'}} - \frac{6}{x} y = \frac{y ^{4}}{x ^{15}}

y = \frac{3 4 x ^{6}}{3 - 3 x ^{4} + c _{1}}

Solution steps

y^{'} (x) - \frac{6}{x} y = \frac{y ^{4}}{x ^{15}}

Solve Bernoulli ODE:

y = \frac{3 4 x ^{6}}{3 - 3 x ^{4} + c _{1}}

y = \frac{3 4 x ^{6}}{3 - 3 x ^{4} + c _{1}}

- 6 sin (t)

ln (e^{x} + x)

4 x y^{^{'}} + y = 20 x

\int \frac{( x ^{2} - 2 x + 5 )}{x ^{2}} d x

x \to 0 lim (\frac{e x - 1}{x})

What is the solution for y^'-6/x y=(y^4)/(x^{15)} ?
The solution for y^'-6/x y=(y^4)/(x^{15)} is y=(\sqrt[3]{4}x^6)/(\sqrt[3]{-3x^4+c_{1)}}