What is the integral of (ln(7x))/(x^9) ?

The integral of (ln(7x))/(x^9) is -(ln(7x))/(8x^8)-1/(64x^8)+C

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integral of (ln(7x))/(x^9)

\int \frac{ln ( 7 x )}{x ^{9}} d x

- \frac{ln ( 7 x )}{8 x ^{8}} - \frac{1}{64 x ^{8}} + C

Solution steps

\int \frac{ln ( 7 x )}{x ^{9}} d x

Apply Integration By Parts

: - \frac{ln ( 7 x )}{8 x ^{8}} - \int - \frac{1}{8 x ^{9}} d x

= - \frac{ln ( 7 x )}{8 x ^{8}} - \int - \frac{1}{8 x ^{9}} d x

\int - \frac{1}{8 x ^{9}} d x = \frac{1}{64 x ^{8}}

= - \frac{ln ( 7 x )}{8 x ^{8}} - \frac{1}{64 x ^{8}}

Add a constant to the solution

= - \frac{ln ( 7 x )}{8 x ^{8}} - \frac{1}{64 x ^{8}} + C

ln (x x^{2} - 1)

(- 3, - 2), (1, - 5)

\int cos (x) (1 + 7 sin^{2} (x)) d x

ln (2 x)

n = 0 \sum \infty \frac{1}{n ^{4} + 6}

What is the integral of (ln(7x))/(x^9) ?
The integral of (ln(7x))/(x^9) is -(ln(7x))/(8x^8)-1/(64x^8)+C