What is the integral of 5e^{2-x} ?

The integral of 5e^{2-x} is -5e^{2-x}+C

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integral of 5e^{2-x}

\int 5 e^{2 - x} d x

- 5 e^{2 - x} + C

Solution steps

\int 5 e^{2 - x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int e^{2 - x} d x

Apply u-substitution

: \int - e^{u} d u

= 5 \cdot \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 (- \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 5 (- e^{u})

Substitute back

u = 2 - x

= 5 (- e^{2 - x})

Simplify

= - 5 e^{2 - x}

Add a constant to the solution

= - 5 e^{2 - x} + C

f (θ) = 2 θ

\int \frac{5}{x - 3} d x

\int 8^{s i n (x)} cos (x) d x

\frac{d}{d x} (4 x^{3} - 26 x^{2} + 40 x)

y^{^{''}} + 5 y^{^{'}} + 4 y = - 19 t e^{5 t}