What is the integral of 5/(x-3) ?

The integral of 5/(x-3) is 5ln|x-3|+C

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integral of 5/(x-3)

\int \frac{5}{x - 3} d x

5 ln ∣ x - 3 ∣ + C

Solution steps

\int \frac{5}{x - 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{x - 3} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 5 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 5 ln ∣ u ∣

Substitute back

u = x - 3

= 5 ln ∣ x - 3 ∣

Add a constant to the solution

= 5 ln ∣ x - 3 ∣ + C

\int 8^{s i n (x)} cos (x) d x

\frac{d}{d x} (4 x^{3} - 26 x^{2} + 40 x)

y^{^{''}} + 5 y^{^{'}} + 4 y = - 19 t e^{5 t}

\frac{d}{d x} (x^{3} - 3 x^{2} + 1)

\frac{d}{d x} (ln (1 + x^{2}))