What is the derivative of 4x^2cos(x-x) ?

The derivative of 4x^2cos(x-x) is 4(2xcos(x)-x^2sin(x))-1

What is the first derivative of 4x^2cos(x-x) ?

The first derivative of 4x^2cos(x-x) is 4(2xcos(x)-x^2sin(x))-1

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\frac{d}{d x} (4 x^{2} cos (x) - x)

4 (2 x cos (x) - x^{2} sin (x)) - 1

Solution steps

\frac{d}{d x} (4 x^{2} cos (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2} cos (x)) - \frac{d x}{d x}

\frac{d}{d x} (4 x^{2} cos (x)) = 4 (2 x cos (x) - x^{2} sin (x))

\frac{d x}{d x} = 1

= 4 (2 x cos (x) - x^{2} sin (x)) - 1

\frac{d ^{2}}{d x ^{2}} (x^{2} + y^{2})

f (x) = 7 x + 4

f (x) = - 2 sin (x), at x = - π

\int_{0}^{10} x^{2} - 6 x + 5 d x

n = 1 \sum \infty \frac{1}{100 n}

What is the derivative of 4x^2cos(x-x) ?
The derivative of 4x^2cos(x-x) is 4(2xcos(x)-x^2sin(x))-1
What is the first derivative of 4x^2cos(x-x) ?
The first derivative of 4x^2cos(x-x) is 4(2xcos(x)-x^2sin(x))-1