What is the limit as x approaches 1 of (sqrt(x)-8)/(\sqrt[3]{x)-4} ?

The limit as x approaches 1 of (sqrt(x)-8)/(\sqrt[3]{x)-4} is 7/3

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limit as x approaches 1 of (sqrt(x)-8)/(\sqrt[3]{x)-4}

x \to 1 lim (\frac{x - 8}{3 x - 4})

\frac{7}{3}

Decimal

2.33333 \dots

Solution steps

x \to 1 lim (\frac{x - 8}{3 x - 4})

Plug in the value

x = 1

= \frac{1 - 8}{3 1 - 4}

Simplify

\frac{1 - 8}{3 1 - 4} : \frac{7}{3}

= \frac{7}{3}

\int (x^{2} - 5 x) e^{x} d x

5 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0

\frac{\partial}{\partial x} (2 x^{2} yz)

\frac{d}{d x} (ln (5 x^{2} + 6))

\frac{\partial}{\partial y} (x y + z)

What is the limit as x approaches 1 of (sqrt(x)-8)/(\sqrt[3]{x)-4} ?
The limit as x approaches 1 of (sqrt(x)-8)/(\sqrt[3]{x)-4} is 7/3