What is the solution for (8-6y+e^{-3x})dx-2dy=0 ?

The solution for (8-6y+e^{-3x})dx-2dy=0 is y= x/(2e^{3x)}+4/3+(c_{1})/(e^{3x)}

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(8-6y+e^{-3x})dx-2dy=0

(8 - 6 y + e^{- 3 x}) d x - 2 d y = 0

y = \frac{x}{2 e ^{3 x}} + \frac{4}{3} + \frac{c _{1}}{e ^{3 x}}

Solution steps

(8 - 6 y + e^{- 3 x}) d x - 2 d y = 0

Solve linear ODE:

y = \frac{x}{2 e ^{3 x}} + \frac{4}{3} + \frac{c _{1}}{e ^{3 x}}

y = \frac{x}{2 e ^{3 x}} + \frac{4}{3} + \frac{c _{1}}{e ^{3 x}}

\int (\frac{x}{( x - 2 ) ( x - 3 )}) d x

f (x) = e^{x} x^{- n}

\frac{d}{d x} ((3 x - x^{3} + 1)^{4})

\frac{d}{d t} (s sin (t))

\int_{0}^{500} 6 (700 y - y^{2}) d y

What is the solution for (8-6y+e^{-3x})dx-2dy=0 ?
The solution for (8-6y+e^{-3x})dx-2dy=0 is y= x/(2e^{3x)}+4/3+(c_{1})/(e^{3x)}