What is the derivative of f(x)=-2x^2-20x-48 ?

The derivative of f(x)=-2x^2-20x-48 is -4x-20

What is the first derivative of f(x)=-2x^2-20x-48 ?

The first derivative of f(x)=-2x^2-20x-48 is -4x-20

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derivative of

f (x) = - 2 x^{2} - 20 x - 48

- 4 x - 20

Solution steps

\frac{d}{d x} (- 2 x^{2} - 20 x - 48)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (20 x) - \frac{d}{d x} (48)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (20 x) = 20

\frac{d}{d x} (48) = 0

= - 4 x - 20 - 0

Simplify

= - 4 x - 20

f (x) = - 4 cos (x), at x = \frac{π}{2}

\int x^{2} e^{2} x d x

\int (x^{2} - 1) e^{x} d x

\frac{\partial}{\partial x} (3 x^{2} + 9 y^{2} - x y + x)

\int \frac{x ^{3} + 5 x ^{4} - 7 x}{x ^{2}} d x

What is the derivative of f(x)=-2x^2-20x-48 ?
The derivative of f(x)=-2x^2-20x-48 is -4x-20
What is the first derivative of f(x)=-2x^2-20x-48 ?
The first derivative of f(x)=-2x^2-20x-48 is -4x-20