What is the solution for (5y^2-xy)dx+(x^2)dy=0 ?

The solution for (5y^2-xy)dx+(x^2)dy=0 is y= x/(5ln(x)+c_{1)}

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(5y^2-xy)dx+(x^2)dy=0

(5 y^{2} - x y) d x + (x^{2}) d y = 0

y = \frac{x}{5 ln ( x ) + c _{1}}

Solution steps

(5 y^{2} - x y) d x + (x^{2}) d y = 0

Solve Bernoulli ODE:

y = \frac{x}{5 ln ( x ) + c _{1}}

y = \frac{x}{5 ln ( x ) + c _{1}}

y^{^{''}} - 3 y^{^{'}} = 8

x \to 1 - lim ((x - 2)^{2})

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2} - 15)

h (x) = \frac{1}{( - 3 x ^{2} + 3 x - 2 ) ^{3}}

126 x (9 x^{2} + 6)^{6}

What is the solution for (5y^2-xy)dx+(x^2)dy=0 ?
The solution for (5y^2-xy)dx+(x^2)dy=0 is y= x/(5ln(x)+c_{1)}