What is (\partial)/(\partial x)(3x^2+3y^2-15) ?

The answer to (\partial)/(\partial x)(3x^2+3y^2-15) is 6x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(3x^2+3y^2-15)

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2} - 15)

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2} - 15)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (3 y^{2}) - \frac{\partial}{\partial x} (15)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (15) = 0

= 6 x + 0 - 0

Simplify

= 6 x

h (x) = \frac{1}{( - 3 x ^{2} + 3 x - 2 ) ^{3}}

126 x (9 x^{2} + 6)^{6}

\int 20 tan^{3} (x) d x

\int_{- 1}^{0} x + 1 d x

y = x + 1, y = 7 x - 17, y = - 2 x - 2

What is (\partial)/(\partial x)(3x^2+3y^2-15) ?
The answer to (\partial)/(\partial x)(3x^2+3y^2-15) is 6x