y^{''}-3y^'=8

Lösung

y^{^{''}} - 3 y^{^{'}} = 8

y = c_{1} e^{3 t} + c_{2} - \frac{8 t}{3}

Schritte zur Lösung

y^{''} (t) - 3 y^{'} (t) = 8

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} - \frac{8 t}{3}

y = c_{1} e^{3 t} + c_{2} - \frac{8 t}{3}

x \to 1 - lim ((x - 2)^{2})

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2} - 15)

h (x) = \frac{1}{( - 3 x ^{2} + 3 x - 2 ) ^{3}}

126 x (9 x^{2} + 6)^{6}

\int 20 tan^{3} (x) d x