What is the derivative of 126x(9x^2+6)^6 ?

The derivative of 126x(9x^2+6)^6 is 126((9x^2+6)^6+108x^2(9x^2+6)^5)

What is the first derivative of 126x(9x^2+6)^6 ?

The first derivative of 126x(9x^2+6)^6 is 126((9x^2+6)^6+108x^2(9x^2+6)^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

126 x (9 x^{2} + 6)^{6}

126 ((9 x^{2} + 6)^{6} + 108 x^{2} (9 x^{2} + 6)^{5})

Solution steps

\frac{d}{d x} (126 x (9 x^{2} + 6)^{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 126 \frac{d}{d x} (x (9 x^{2} + 6)^{6})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (9 x^{2} + 6)^{6}

= 126 (\frac{d x}{d x} (9 x^{2} + 6)^{6} + \frac{d}{d x} ((9 x^{2} + 6)^{6}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} ((9 x^{2} + 6)^{6}) = 108 x (9 x^{2} + 6)^{5}

= 126 (1 \cdot (9 x^{2} + 6)^{6} + 108 x (9 x^{2} + 6)^{5} x)

Simplify

126 (1 \cdot (9 x^{2} + 6)^{6} + 108 x (9 x^{2} + 6)^{5} x) : 126 ((9 x^{2} + 6)^{6} + 108 x^{2} (9 x^{2} + 6)^{5})

= 126 ((9 x^{2} + 6)^{6} + 108 x^{2} (9 x^{2} + 6)^{5})

\int 20 tan^{3} (x) d x

\int_{- 1}^{0} x + 1 d x

y = x + 1, y = 7 x - 17, y = - 2 x - 2

y = ∣ 9 x ∣, y = x^{2} - 10

\int \frac{2 x + 1}{x ^{2} + 4} d x

What is the derivative of 126x(9x^2+6)^6 ?
The derivative of 126x(9x^2+6)^6 is 126((9x^2+6)^6+108x^2(9x^2+6)^5)
What is the first derivative of 126x(9x^2+6)^6 ?
The first derivative of 126x(9x^2+6)^6 is 126((9x^2+6)^6+108x^2(9x^2+6)^5)