What is the integral from-1 to 1 of x/(sqrt(x^2+25)) ?

The integral from-1 to 1 of x/(sqrt(x^2+25)) is 0

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integral from-1 to 1 of x/(sqrt(x^2+25))

\int_{- 1}^{1} \frac{x}{x ^{2} + 25} d x

0

Solution steps

\int_{- 1}^{1} \frac{x}{x ^{2} + 25} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x}{x ^{2} + 25} :

Odd

= 0

\frac{\partial}{\partial z} (y^{2} e^{x yz})

\int_{1}^{\infty} \frac{1}{x ^{2} + 4} d x

\frac{\partial}{\partial x} (x^{2} + x y + y^{2} - 6 x + 2)

\int \frac{e ^{2} x}{4 + e ^{4} x} d x

\frac{d y}{d x} = \frac{( 2 x + 1 )}{2 y}

What is the integral from-1 to 1 of x/(sqrt(x^2+25)) ?
The integral from-1 to 1 of x/(sqrt(x^2+25)) is 0