What is the integral of cos(x+y+z) ?

The integral of cos(x+y+z) is sin(x+y+z)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos(x+y+z)

\int cos (x + y + z) d z

sin (x + y + z) + C

Solution steps

\int cos (x + y + z) d z

Apply u-substitution

: \int cos (u) d u

= \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= sin (u)

Substitute back

u = x + y + z

= sin (x + y + z)

Add a constant to the solution

= sin (x + y + z) + C

\frac{\partial}{\partial x} (sin (π (2 x - 2 y)))

\int 2 x y + y^{2}

f (x) = 3 x^{2} - 5 x, (2, 2)

\int \frac{sec ( x ) + cos ( x )}{9 cos ( x )} d x

3 x^{4} + 2 x^{3} + x^{2} - 2