What is the solution for (x^2+1)(dy)/(dx)+xy-3x=0 ?

The solution for (x^2+1)(dy)/(dx)+xy-3x=0 is y=(c_{1})/(sqrt(x^2+1))+3

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(x^2+1)(dy)/(dx)+xy-3x=0

(x^{2} + 1) \frac{d y}{d x} + x y - 3 x = 0

y = \frac{c _{1}}{x ^{2} + 1} + 3

Solution steps

(x^{2} + 1) \frac{d y}{d x} + x y - 3 x = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} + 1} + 3

y = \frac{c _{1}}{x ^{2} + 1} + 3

\frac{d}{d x} ((\frac{x}{x + 1})^{2})

\int \frac{x ^{2} - 4 x}{( x - 2 ) ^{3}} d x

e^{- 6 x}

\frac{d}{d x} (x^{2} - \frac{y}{4})

h (x) = lo g_{9} (x)

What is the solution for (x^2+1)(dy)/(dx)+xy-3x=0 ?
The solution for (x^2+1)(dy)/(dx)+xy-3x=0 is y=(c_{1})/(sqrt(x^2+1))+3