What is the derivative of x^2-y/4 ?

The derivative of x^2-y/4 is 2x-((dy)/(dx))/4

What is the first derivative of x^2-y/4 ?

The first derivative of x^2-y/4 is 2x-((dy)/(dx))/4

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\frac{d}{d x} (x^{2} - \frac{y}{4})

2 x - \frac{\frac{d y}{d x}}{4}

Solution steps

\frac{d}{d x} (x^{2} - \frac{y}{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (\frac{y}{4})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{y}{4}) = \frac{\frac{d y}{d x}}{4}

= 2 x - \frac{\frac{d y}{d x}}{4}

h (x) = lo g_{9} (x)

\frac{d}{d x} (7 cos (x) + 3 e^{x})

y = 1 + cot^{2} (x)

\frac{d}{d x} (e^{2 x} + e^{3 x})

\int \frac{- 2200 x}{25 - x ^{2}} d x

What is the derivative of x^2-y/4 ?
The derivative of x^2-y/4 is 2x-((dy)/(dx))/4
What is the first derivative of x^2-y/4 ?
The first derivative of x^2-y/4 is 2x-((dy)/(dx))/4