What is the derivative of y=ln(30)+30^{x+4} ?

The derivative of y=ln(30)+30^{x+4} is ln(30)*30^{x+4}

What is the first derivative of y=ln(30)+30^{x+4} ?

The first derivative of y=ln(30)+30^{x+4} is ln(30)*30^{x+4}

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derivative of

y = ln (30) + 3 0^{x + 4}

ln (30) \cdot 3 0^{x + 4}

Solution steps

\frac{d}{d x} (ln (30) + 3 0^{x + 4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (30)) + \frac{d}{d x} (3 0^{x + 4})

\frac{d}{d x} (ln (30)) = 0

\frac{d}{d x} (3 0^{x + 4}) = ln (30) \cdot 3 0^{x + 4}

= 0 + ln (30) \cdot 3 0^{x + 4}

Simplify

= ln (30) \cdot 3 0^{x + 4}

x \to 4 lim (x^{2} - 16)

\int 3 x - 8 d x

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - y^{2})

x \to - \infty lim (- \frac{1}{x})

What is the derivative of y=ln(30)+30^{x+4} ?
The derivative of y=ln(30)+30^{x+4} is ln(30)*30^{x+4}
What is the first derivative of y=ln(30)+30^{x+4} ?
The first derivative of y=ln(30)+30^{x+4} is ln(30)*30^{x+4}