What is the derivative of f(t)=t^2-sqrt(t)+1 ?

The derivative of f(t)=t^2-sqrt(t)+1 is 2t-1/(2sqrt(t))

What is the first derivative of f(t)=t^2-sqrt(t)+1 ?

The first derivative of f(t)=t^2-sqrt(t)+1 is 2t-1/(2sqrt(t))

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derivative of

f (t) = t^{2} - t + 1

2 t - \frac{1}{2 t}

Solution steps

\frac{d}{d t} (t^{2} - t + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) - \frac{d}{d t} (t) + \frac{d}{d t} (1)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (t) = \frac{1}{2 t}

\frac{d}{d t} (1) = 0

= 2 t - \frac{1}{2 t} + 0

Simplify

= 2 t - \frac{1}{2 t}

\frac{\partial}{\partial x} (\frac{y - x}{z})

\frac{d}{d x} ((x - 2) (x + 2))

t \frac{d y}{d t} - 3 y = \frac{4 t ^{5}}{t ^{2} + 4}

\int 11 sin^{3} (x co) s^{2} x d x

\int \frac{y ^{2}}{y - 1} d y

What is the derivative of f(t)=t^2-sqrt(t)+1 ?
The derivative of f(t)=t^2-sqrt(t)+1 is 2t-1/(2sqrt(t))
What is the first derivative of f(t)=t^2-sqrt(t)+1 ?
The first derivative of f(t)=t^2-sqrt(t)+1 is 2t-1/(2sqrt(t))