What is the integral of (((100+x)/(50))-17.33) ?

The integral of (((100+x)/(50))-17.33) is 0.01x^2-15.33x+C

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integral of (((100+x)/(50))-17.33)

\int ((\frac{100 + x}{50}) - 17.33) d x

0.01 x^{2} - 15.33 x + C

Solution steps

\int \frac{100 + x}{50} - 17.33 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{100 + x}{50} d x - \int 17.33 d x

\int \frac{100 + x}{50} d x = \frac{1}{50} (100 x + \frac{x ^{2}}{2})

\int 17.33 d x = 17.33 x

= \frac{1}{50} (100 x + \frac{x ^{2}}{2}) - 17.33 x

Simplify

\frac{1}{50} (100 x + \frac{x ^{2}}{2}) - 17.33 x : 0.01 x^{2} - 15.33 x

= 0.01 x^{2} - 15.33 x

Add a constant to the solution

= 0.01 x^{2} - 15.33 x + C

\frac{d}{d x} (2 A x)

y^{^{'}} = 2 y - 3 y^{2}

\frac{d y}{d x} = x + 8

\frac{1}{2 ( s + 1 )}

(2.8) (0.6)

What is the integral of (((100+x)/(50))-17.33) ?
The integral of (((100+x)/(50))-17.33) is 0.01x^2-15.33x+C