What is the first derivative of 2Inx ?

The first derivative of 2Inx is 2nI

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derivative of 2Inx

\frac{d}{d x} (2 I n x)

2 n I

Solution steps

\frac{d}{d x} (2 I n x)

Treat

n, I

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 I n \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 I n \cdot 1

Simplify

= 2 n I

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