What is the derivative of x^4-1/x ?

The derivative of x^4-1/x is 4x^3+1/(x^2)

What is the first derivative of x^4-1/x ?

The first derivative of x^4-1/x is 4x^3+1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{4} - \frac{1}{x})

4 x^{3} + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{4} - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 4 x^{3} - (- \frac{1}{x ^{2}})

Simplify

= 4 x^{3} + \frac{1}{x ^{2}}

x \to 4 lim (x^{2} - 4 x + 1)

f (x) = 3 x - 5

\int \frac{16 x ^{2}}{( x - 9 ) ( x + 3 ) ^{2}} d x

\frac{d}{d x} ((5 x - 4) (2 x^{3} - x^{2} + 1))

f (x) = \frac{1}{4 + 3 x}, (1, \frac{1}{7})

What is the derivative of x^4-1/x ?
The derivative of x^4-1/x is 4x^3+1/(x^2)
What is the first derivative of x^4-1/x ?
The first derivative of x^4-1/x is 4x^3+1/(x^2)