What is the limit as x approaches 1 of ((x+1))/(x-1) ?

The limit as x approaches 1 of ((x+1))/(x-1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of ((x+1))/(x-1)

x \to 1 lim (\frac{( x + 1 )}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{x + 1}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{x + 1}{x - 1}) = \infty

x \to 1 - lim (\frac{x + 1}{x - 1}) = - \infty

= diverges

\frac{d}{d x} (x^{2} - \frac{1}{8} ln (x))

\int e^{- 2 t} t d t

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{( e ^{- 3 x} )}{x}

\int \frac{( x ^{2} )}{x ^{2} + 64} d x

\frac{d}{d x} (\frac{- x + 6}{2 ( 2 - x ) 2 - x})

What is the limit as x approaches 1 of ((x+1))/(x-1) ?
The limit as x approaches 1 of ((x+1))/(x-1) is diverges