What is area e^{5x},e^{7x},x=1 ?

The answer to area e^{5x},e^{7x},x=1 is (5e^7-7e^5+2)/(35)

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area e^{5x},e^{7x},x=1

area

e^{5 x}, e^{7 x}, x = 1

\frac{5 e ^{7} - 7 e ^{5} + 2}{35}

Decimal Notation

127.03639 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{5 x} - e^{7 x} d x

Solve

\int_{0}^{1} e^{5 x} - e^{7 x} d x : \frac{5 e ^{7} - 7 e ^{5} + 2}{35}

The area is:

= \frac{5 e ^{7} - 7 e ^{5} + 2}{35}

y = \frac{2}{x}, (1, 2)

\int 6 x + sin (x) d x

\frac{\partial}{\partial y} (2 y^{2} x - 3)

\int x (x + 1)^{3} d x

\frac{d}{d x} (0.5 e^{x - 1})

What is area e^{5x},e^{7x},x=1 ?
The answer to area e^{5x},e^{7x},x=1 is (5e^7-7e^5+2)/(35)