What is the integral from 0 to 7 of sqrt(x^2-49) ?

The integral from 0 to 7 of sqrt(x^2-49) is -Does not exist

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integral from 0 to 7 of sqrt(x^2-49)

\int_{0}^{7} x^{2} - 49 d x

- Does not exist

Solution steps

\int_{0}^{7} x^{2} - 49 d x

Compute the indefinite integral:

\int x^{2} - 49 d x = 49 (\frac{1}{98} x x^{2} - 49 - \frac{1}{2} ln (\frac{x + x ^{2} - 49}{7})) + C

Compute the boundaries:

\int_{0}^{7} x^{2} - 49 d x = 0 -

Does not exist

= 0 - Does not exist

Simplify

= - Does not exist

\frac{d ^{2}}{d x ^{2}} (x^{2} + 64)

\int 7 ln (x^{2} - x + 8) d x

\frac{d}{d x} (a x^{3} + b x^{2} + c)

\frac{d y}{d x} = e^{2 x} - 3 y, y (0) = 1

4 sec (x) - 8 cos (x)

What is the integral from 0 to 7 of sqrt(x^2-49) ?
The integral from 0 to 7 of sqrt(x^2-49) is -Does not exist