What is the integral from 0 to 7 of sqrt(x^2-49) ?

The integral from 0 to 7 of sqrt(x^2-49) is -Does not exist

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integral from 0 to 7 of sqrt(x^2-49)

\int_{0}^{7} x^{2} - 49 d x

- Does not exist

Solution steps

\int_{0}^{7} x^{2} - 49 d x

Compute the indefinite integral:

\int x^{2} - 49 d x = 49 (\frac{1}{98} x x^{2} - 49 - \frac{1}{2} ln (\frac{x + x ^{2} - 49}{7})) + C

Compute the boundaries:

\int_{0}^{7} x^{2} - 49 d x = 0 -

Does not exist

= 0 - Does not exist

Simplify

= - Does not exist

x \frac{d y}{d x} = y + 2 x y

\frac{d ^{2}}{d x ^{2}} (x^{2} + 64)

\frac{d y}{d x} + 0.7 x = 18.2

- 4 y^{^{''}} + 16 y = 0, y (- 1) = - 1, y^{^{'}} (1) = - 1

\int 7 ln (x^{2} - x + 8) d x

What is the integral from 0 to 7 of sqrt(x^2-49) ?
The integral from 0 to 7 of sqrt(x^2-49) is -Does not exist