What is the derivative of 4sec(x)-8cos(x) ?

The derivative of 4sec(x)-8cos(x) is 4sec(x)tan(x)+8sin(x)

What is the first derivative of 4sec(x)-8cos(x) ?

The first derivative of 4sec(x)-8cos(x) is 4sec(x)tan(x)+8sin(x)

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derivative of

4 sec (x) - 8 cos (x)

4 sec (x) tan (x) + 8 sin (x)

Solution steps

\frac{d}{d x} (4 sec (x) - 8 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 sec (x)) - \frac{d}{d x} (8 cos (x))

\frac{d}{d x} (4 sec (x)) = 4 sec (x) tan (x)

\frac{d}{d x} (8 cos (x)) = - 8 sin (x)

= 4 sec (x) tan (x) - (- 8 sin (x))

Simplify

= 4 sec (x) tan (x) + 8 sin (x)

\int_{0}^{1} x e^{- 7 x^{2}} d x

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\int \frac{1}{- y ^{\frac{2}{3}}} d y

x \to 0 lim (3 x^{\frac{x}{2}})

\int \frac{e ^{c o s^{2} (x)}}{csc ( 2 x )} d x

What is the derivative of 4sec(x)-8cos(x) ?
The derivative of 4sec(x)-8cos(x) is 4sec(x)tan(x)+8sin(x)
What is the first derivative of 4sec(x)-8cos(x) ?
The first derivative of 4sec(x)-8cos(x) is 4sec(x)tan(x)+8sin(x)