What is the solution for (dy)/(dx)=e^{2x}-3y,y(0)=1 ?

The solution for (dy)/(dx)=e^{2x}-3y,y(0)=1 is y=(e^{2x})/5+4/(5e^{3x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=e^{2x}-3y,y(0)=1

\frac{d y}{d x} = e^{2 x} - 3 y, y (0) = 1

y = \frac{e ^{2 x}}{5} + \frac{4}{5 e ^{3 x}}

Solution steps

\frac{d y}{d x} = e^{2 x} - 3 y

Solve linear ODE:

y = \frac{e ^{2 x}}{5} + \frac{4}{5 e ^{3 x}}

y = \frac{e ^{2 x}}{5} + \frac{4}{5 e ^{3 x}}

4 sec (x) - 8 cos (x)

\int_{0}^{1} x e^{- 7 x^{2}} d x

\int (x + 5) (4 x - 2) d x

\int \frac{1}{- y ^{\frac{2}{3}}} d y

x \to 0 lim (3 x^{\frac{x}{2}})

What is the solution for (dy)/(dx)=e^{2x}-3y,y(0)=1 ?
The solution for (dy)/(dx)=e^{2x}-3y,y(0)=1 is y=(e^{2x})/5+4/(5e^{3x)}