What is the derivative of tan(2x+1) ?

The derivative of tan(2x+1) is sec^2(2x+1)*2

What is the first derivative of tan(2x+1) ?

The first derivative of tan(2x+1) is sec^2(2x+1)*2

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\frac{d}{d x} (tan (2 x + 1))

sec^{2} (2 x + 1) \cdot 2

Solution steps

\frac{d}{d x} (tan (2 x + 1))

Apply the chain rule:

sec^{2} (2 x + 1) \frac{d}{d x} (2 x + 1)

= sec^{2} (2 x + 1) \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= sec^{2} (2 x + 1) \cdot 2

y = x^{3} + 6 x

4 + x^{6}

f (x) = 2 x 4 - x^{2}

x \to 2 lim (- x^{2} + 6 x - 4)

y = 6 x - 2, (1, 3)

What is the derivative of tan(2x+1) ?
The derivative of tan(2x+1) is sec^2(2x+1)*2
What is the first derivative of tan(2x+1) ?
The first derivative of tan(2x+1) is sec^2(2x+1)*2