What is the derivative of 4x^{5/4}+8x^{3/2}+9x ?

The derivative of 4x^{5/4}+8x^{3/2}+9x is 5x^{1/4}+12x^{1/2}+9

What is the first derivative of 4x^{5/4}+8x^{3/2}+9x ?

The first derivative of 4x^{5/4}+8x^{3/2}+9x is 5x^{1/4}+12x^{1/2}+9

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derivative of

4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 9 x

5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 9

Solution steps

\frac{d}{d x} (4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{5}{4}}) + \frac{d}{d x} (8 x^{\frac{3}{2}}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (4 x^{\frac{5}{4}}) = 5 x^{\frac{1}{4}}

\frac{d}{d x} (8 x^{\frac{3}{2}}) = 12 x^{\frac{1}{2}}

\frac{d}{d x} (9 x) = 9

= 5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 9

ln (x - 1)

\frac{d y}{d t} = \frac{e ^{y} + 1}{e ^{y}}

x \to 2 - lim (2 x - 3)

y = 1 - cot (2 x)

x \frac{d y}{d x} = \frac{1 - y ^{2}}{2 y}

What is the derivative of 4x^{5/4}+8x^{3/2}+9x ?
The derivative of 4x^{5/4}+8x^{3/2}+9x is 5x^{1/4}+12x^{1/2}+9
What is the first derivative of 4x^{5/4}+8x^{3/2}+9x ?
The first derivative of 4x^{5/4}+8x^{3/2}+9x is 5x^{1/4}+12x^{1/2}+9