What is the solution for (dy)/(dt)=(e^y+1)/(e^y) ?

The solution for (dy)/(dt)=(e^y+1)/(e^y) is y=ln(e^{t+c_{1}}-1)

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(dy)/(dt)=(e^y+1)/(e^y)

\frac{d y}{d t} = \frac{e ^{y} + 1}{e ^{y}}

y = ln (e^{t + c_{1}} - 1)

Solution steps

\frac{d y}{d t} = \frac{e ^{y} + 1}{e ^{y}}

Solve separable ODE:

y = ln (e^{t + c_{1}} - 1)

y = ln (e^{t + c_{1}} - 1)

x \to 2 - lim (2 x - 3)

y = 1 - cot (2 x)

x \frac{d y}{d x} = \frac{1 - y ^{2}}{2 y}

\int_{0}^{4} \frac{4 t}{( t - 5 ) ^{2}} d t

y^{^{'}} + 4 y = 8

What is the solution for (dy)/(dt)=(e^y+1)/(e^y) ?
The solution for (dy)/(dt)=(e^y+1)/(e^y) is y=ln(e^{t+c_{1}}-1)