What is the derivative of 1+7,x-tan(x) ?

The derivative of 1+7,x-tan(x) is 0+(7,1)-sec^2(x)

What is the first derivative of 1+7,x-tan(x) ?

The first derivative of 1+7,x-tan(x) is 0+(7,1)-sec^2(x)

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\frac{d}{d x} (1 + 7, x - tan (x))

0 + (7, 1) - sec^{2} (x)

Solution steps

\frac{d}{d x} (1 + 7, x - tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (7, x) - \frac{d}{d x} (tan (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (7, x) = (7, 1)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 0 + (7, 1) - sec^{2} (x)

\frac{d}{d x} (\frac{x ^{3} + x ^{2}}{x})

\int_{0}^{π} 22 sin^{4} (x) d x

\int \frac{4 x ^{2}}{4 - x ^{2}} d x

\int \frac{3}{2} t^{2} d t

f (x) = - 3 x^{2} - 2, at x = 5

What is the derivative of 1+7,x-tan(x) ?
The derivative of 1+7,x-tan(x) is 0+(7,1)-sec^2(x)
What is the first derivative of 1+7,x-tan(x) ?
The first derivative of 1+7,x-tan(x) is 0+(7,1)-sec^2(x)