What is the integral from 0 to pi of 22sin^4(x) ?

The integral from 0 to pi of 22sin^4(x) is (33pi)/4

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integral from 0 to pi of 22sin^4(x)

\int_{0}^{π} 22 sin^{4} (x) d x

\frac{33 π}{4}

Solution steps

\int_{0}^{π} 22 sin^{4} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 22 \cdot \int_{0}^{π} sin^{4} (x) d x

Apply Integral Reduction

= 22 (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \int_{0}^{π} sin^{2} (x) d x)

\int_{0}^{π} sin^{2} (x) d x = \frac{π}{2}

= 22 (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \frac{π}{2})

Simplify

22 (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \frac{π}{2}) : 22 (- [\frac{1}{4} sin^{3} (x) cos (x)]_{0}^{π} + \frac{3 π}{8})

= 22 (- [\frac{1}{4} sin^{3} (x) cos (x)]_{0}^{π} + \frac{3 π}{8})

Compute the boundaries:

0

= 22 (- 0 + \frac{3 π}{8})

Simplify

= \frac{33 π}{4}

\int \frac{4 x ^{2}}{4 - x ^{2}} d x

\int \frac{3}{2} t^{2} d t

f (x) = - 3 x^{2} - 2, at x = 5

\int - 4 x e^{x^{2}} d x

\frac{3}{( s - 1 ) ^{2}}

What is the integral from 0 to pi of 22sin^4(x) ?
The integral from 0 to pi of 22sin^4(x) is (33pi)/4