What is the solution for (x^2+1)(dy)/(dx)=x^2(y-1) ?

The solution for (x^2+1)(dy)/(dx)=x^2(y-1) is y=e^{-arctan(x)+x+c_{1}}+1

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(x^2+1)(dy)/(dx)=x^2(y-1)

(x^{2} + 1) \frac{d y}{d x} = x^{2} (y - 1)

y = e^{- a r c t a n (x) + x + c_{1}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} = x^{2} (y - 1)

Solve separable ODE:

y = e^{- a r c t a n (x) + x + c_{1}} + 1

y = e^{- a r c t a n (x) + x + c_{1}} + 1

\frac{d}{d x} (x y 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9})

f (x) = \frac{x ^{3} + 2 x ^{2} + x - 1}{x}

n = 0 \sum \infty (- 1)^{n} (2)^{n}

f (x) = x^{2} - 2, - 3, 1

x y^{^{'''}} + 2 y^{^{''}} = 6 x

What is the solution for (x^2+1)(dy)/(dx)=x^2(y-1) ?
The solution for (x^2+1)(dy)/(dx)=x^2(y-1) is y=e^{-arctan(x)+x+c_{1}}+1